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How will you convert benzene into (i)p-nitrobromobenzene (ii)m-nitrochlorobenzene (iii)p-nitrotoluene (iv)acetophenone ? |
Answer» Solution :(i)The two substituents in the benzene ring are present at p-positions. THEREFORE , the sequence of reactions should be such that FIRST an o,p-directing GROUP , i.e., Br atom should be introduced in the benzene ring and this should be followed by nitration. Thus, (II)Here, since the two substituents are at m-position w.r.t. each other , therefore , the first substituent in the benzene ring should be a m-directing group (i.e., `NO_2`) and then the other group (i.e., Cl) should be introduced. Therefore , the sequence of reactions is :  (iii)Here, since the two substituents are at p-position w.r.t. each other , therefore , the first substituent in the benzene ring should be a o,p-directing group (i.e. , `CH_3`) and then the other group (i.e., `NO_2`) should be introduced.  (iv)Acetophenone can be prepared by F.C. acylation using EITHER acetyl chloride or acetic anhydride  or 
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