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| 1. |
How would you calculate the ph of 0.001M NaOH?? |
| Answer» NaOH is a strong base that dissociates completely Therefore [OH-] = [NaOH] = 0.001M First calculate the pOH of the solution : pOH = -log [OH-] pOH = -log 0.001 pOH = 3.00 pH = 14.00 - pOH pH = 14.00 - 3.00 pH = 11.00 | |