InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
How would you determine the standard reduction potential of the system `Mg^(2+)|Mg`? |
|
Answer» A cell will be set up consisting of `Mg//MgSO_(4)(1M)` as one electrode and standard hydrogen electrode Pt, H, (1atm) `H^(+)//(1M)` as second electrode, measure the EMF of the cell and also note the direction of deflection in the voltmeter. The direction of deflection shows that `e^(-1)` s flow from mg electrode to hydrogen electrode, i.e., oxidation takes place on magnesium electrode and reductio on hydrogen electrode. Hence, the cell may be represetned as follows. `Mg|Mg^(2+)(1M)||H^(+)(1M)|H_(2),(1atm),Pt` `E_(Cell)^(@)=E_(H^(+)//(1)/(2)H_(2))^(@)-E_(Mg^(2+)//Mg)^(@)` Put `E_(H^(+)//(1)/(2)H_(2))^(@)=0` `thereforeE_(Mg^(2+)//Mg)^(@)=-E_(cell)^(@)` |
|