1.

How would you explain the following observations ? BaO is soluble but BaSO_(4) is insoluble in water.

Answer»

SOLUTION :BaO is SOLUBLE in water, but `BaSO_(4)` is not. `Ba^(2+)`is a LARGE cation and `O^(2-)`is a small anion. The size compatibility of `Ba^(2+)` and `O^(2-)`is not HIGH. As a result, BaO is unstable. The lattice energy released during its formation is also not very large. It can easily be overcome by the hydration energy of the ions. Therefore, BaO is soluble in water. In `BaSO_(4), Ba^(2+) and SO_(4)^(2-)`are both largesized. The lattice energy released is high. Hence, it is not soluble in water.


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