1.

How would you explain the given observations? BeO is almost insoluble but BeSO_4, is soluble in water.

Answer»

Solution :`O^(2-)` is smaller in size than `SO_4^(2-)`. Consequently, SMALL `Be^(2+)` ion is TIGHTLY packed with small `O^(-)` ion and thus, lattice enthalpy of BeO is GREATER than its hydration enthalpy. So BeO is insoluble in water. On the other HAND, small `Be^(2+)` ion is loosely packed with large `SO_4^(2-)` ion and thus, lattice enthalpy of `BeSO_4` is LESS than its hydration enthalpy. So, `BeSO_4`is soluble in water.


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