1.

`[HXeO_(4)]^(-)+OH^(-)rarr[X]+[Y]+O_(2)+H_(2)O` The products `[X]` and `[Y]` in unbalanced reaction are:A. `[XeO_(6)]^(4-)` and `Xe`B. `[XeO_(6)]^(4-)` and `XeO_(3)`C. `XeO_(3)` and `Xe`D. `H_(2)XeO_(4)` and `Xe`

Answer» Correct Answer - A
Hydrogen xenate ion `[HXeO_(4)]^(-)(OS` of `Xe=+ 6)` disproportionates slowly in solution to give perxenates, `[XeO_(6)]^(4-)(OS"of"Xe=+8)` and xenon.


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