Hydrochloric acid is sold commercially as 12M solution. How many moles and how many grams of HCl are present in 300 mL of 12.0 M solution ?

Hydrochloric acid is sold commercially as 12M solution. How many moles

1.	Hydrochloric acid is sold commercially as 12M solution. How many moles and how many grams of HCl are present in 300 mL of 12.0 M solution ?
Answer» Solution :Molarity of solution `= ("Moles of HCL")/("Volume of solution in LITRES")` `("12 MOL L"^(-1))=("Moles of HCl")/("0.3 L")` Moles of HCl `= ("12 mol L"^(-1))xx("0.3 L")=3.6` mol Mass of HCl `=("3.6 mol")xx("36 G mol"^(-1))=131.4 "g HCl"`.