Hydrogen `(_(1)H^(1))` Deuterium `(_(1)H^(2))` singly omised helium `(_(1)He^(1))` and doubly ionised lithium `(_(1)Li^(6))^(++)` all have one electron around the nucleus Consider an electron transition from `n = 2 to n = 1` if the wavelength of emitted radiartion are `lambda_(1),lambda_(2), lambda_(3),and lambda_(4)`, repectivelly then approximetely which one of the following is correct ?A. `4lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`B. `lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`C. `lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`D. `lambda_(1)=2lambda_(2)=3lambda_(3)=4lambda_(4)`

Hydrogen `(_(1)H^(1))` Deuterium `(_(1)H^(2))` singly omised helium `(

1.	Hydrogen `(_(1)H^(1))` Deuterium `(_(1)H^(2))` singly omised helium `(_(1)He^(1))` and doubly ionised lithium `(_(1)Li^(6))^(++)` all have one electron around the nucleus Consider an electron transition from `n = 2 to n = 1` if the wavelength of emitted radiartion are `lambda_(1),lambda_(2), lambda_(3),and lambda_(4)`, repectivelly then approximetely which one of the following is correct ?A. `4lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`B. `lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`C. `lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`D. `lambda_(1)=2lambda_(2)=3lambda_(3)=4lambda_(4)`
Answer» Correct Answer - C `(1)/(lambda)=RZ^(2)((1)/(1^(2))-(1)/(2^(2)))` `" " (1)/(lambda_(1))=R(1)^(2)(3//4),(1)/(lambda_(2))=R(1)^(2)(3//4)` `" " (1)/(lambda_(3))=R(2)^(2)(3//4),(1)/(lambda_(4))=R3^(2)(3//4)` `" " (1)/(lambda_(1))=(1)/(4lambda_(3))=(1)/(9lambda_(4))=(1)/(lambda_(2))` So, option (c) is correct .