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Hydrogen and oxygen combine to form two compounds, water and hydrogen peroxide. If the percentage of oxygen is 88.89 in water and 94.12 in hydrogen peroxide, show that the data support law of multiple proportions. |
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Answer» Solution :In water, Oxygen = 88.89% `therefore` Hydrogen = 100 - 88.89 = 11.11 % `therefore` 11.11 G of hydrogen combine with oxygen = 88.89 `therefore` 100 g of hydrogen will combine with oxygen `=(88.89)/11.11 xx 100 = 800.1 g` In hydrogen peroxide, Oxygen = 94.12% `therefore` Hydrogen =`100-94.12 = 5.88%` `therefore` 5.88 g of hydrogen combine with oxygen = 94.12 g 100 g of hydrogen will combine with oxygen `=(94.12)/5.88 xx 100 = 1.60 xx 10^(3) g` The ratio in the amounts of oxygen combining with 100 g of hydrogen in the two compounds is therefore, `800.1 : 1.60 xx 10^3` or 1 : 2. Thus, the amounts of oxygen that combine with a fixed amount of hydrogen in `H_2O` and `H_2O_2` are in the SIMPLE whole NUMBER ratio. Hence, the given data SUPPORT law of multiple proportions. |
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