Hydrogen gas is perpared in the laboratory by reacting dilute HCl withgranulated zinc. Following reaction takes place. Zn+2HCl rarr ZnCl_(2) +H_(2) Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn= 65.3 u.

Hydrogen gas is perpared in the laboratory by reacting dilute HCl with

1.	Hydrogen gas is perpared in the laboratory by reacting dilute HCl withgranulated zinc. Following reaction takes place. Zn+2HCl rarr ZnCl_(2) +H_(2) Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn= 65.3 u.
Answer» Solution :Mass of `Zn= 32.65 g` (given) 1 mole of gas `= 22.7` L volume at STP Atomic mass of `Zn= 65.3u` The given EQUATION is `{:(Zn+2HClrarrZnCl_(2)+H_(2)),(65.3g"1 mol "= 22.7 L " at STP"):}` from the above equation 65.3 g Zn, when reacts with HCL, produces `=22.7 L` of `H_(2)` at STP. `:.` 32.65 g Zn, when reacts with HCl, will produce `=(22.7xx32.65)/(65.3) = 11.35L` of `H_(2)` at STP.