Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place `Zn+2HClrarrZnCl_(2)+H_(2)` Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3uA. 10.03 LB. 11.35 LC. 11.57 LD. 9.53 L

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with

1.	Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc, Following reaction takes place `Zn+2HClrarrZnCl_(2)+H_(2)` Calculate the voluem of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of Zn=65 .3uA. 10.03 LB. 11.35 LC. 11.57 LD. 9.53 L
Answer» `underset(65.3g)(Zn) + 2HCl to ZnCl_2 + underset (22.7L)(H_2)` According to the equation, 65.3g of Zn liberates = 22.7 L of `H_2` 32.65g of Zn will liberate `=(22.7)/(65.3)xx32.65=11.35L`

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