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Hydrogen ion concentration of a solution is 2.5xx10^(-4)"mol "dm^(-3)" at "25^(@)C. Calculate its OH^(-) ion concentration. |
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Answer» Solution :We know that `[H_(3)O^(+)][OH^(-)]=10^(-14)" at "25^(@)C` `therefore[OH^(-)]=(10^(-4))/([H_(3)O^(+)])=(10^(-14))/(2.5xx10^(-4))=4xx10^(-11)"MOL"//dm^(3)` |
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