Hydrogen peroxide and water contain 5.93 % and 11.2 % of hydrogen respectively. Show that the data illustrates the law of multiple proportions.

Hydrogen peroxide and water contain 5.93 % and 11.2 % of hydrogen resp

1.	Hydrogen peroxide and water contain 5.93 % and 11.2 % of hydrogen respectively. Show that the data illustrates the law of multiple proportions.
Answer» Solution :In `H_(2)O_(2)` Percentage of `H = 5.93` Percentage of `O = 100 - 5.93 = 94.07` 5.93 g of hydrogen are combined with oxygen = 94.07 g 1.0 g of hydrogen is combined with oxygen `= (94.07)/(5.93) g = 15.86 g` In `H_(2)O` Percentage of `H = 11.2` Percentage of `O = 100 - 11.2 = 88.8 ` 11.2 g of hydrogen are combined with oxygen = 88.8 g 1.0 g of hydrogen is combined with oxygen `= (88.8)/(11.2)g =7.93 g` RATIO by weights of oxygen combining with 1.0gram of hydrogen in thetwo oxides is 15.86 : 7.93 or 2 : 1 Since it is a SIMPLE WHOLE number ratio, the data is according to Law of Multiple PROPORTIONS.