Hydrogen peroxide is ionise as : H_(2)O_(2) hArr H^(+)+HO_(2)^(-). If p^(h) of H_(2)O_(2) is 5.91 at 25^(@)C the ionic product of H_(2)O_(2) is

Hydrogen peroxide is ionise as : H_(2)O_(2) hArr H^(+)+HO_(2)^(-). If

1.	Hydrogen peroxide is ionise as : H_(2)O_(2) hArr H^(+)+HO_(2)^(-). If p^(h) of H_(2)O_(2) is 5.91 at 25^(@)C the ionic product of H_(2)O_(2) is
Answer» `1.51 XX 10^(-12)` `1.15 xx 10^(-12)` `1 xx 10^(-14)` `1.1 xx 10^(-12)` Solution :`[H^(+)]" at" 25^@C =10^(-5.91) = 1.23 xx 10^(-6)M` `[H^(+)] " at" 25^@C = 10^(-5.91) = 1.23 xx 10^(-6) M` `K = [H^(+)][HO_2^(-)] = [1.23 xx 10^(-6)]^2 = 1.51 xx 10^(-12)`