InterviewSolution
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InterviewSolution
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Hydrolysis constant of `NH_(4)^(+)` is `5.55 xx 10^(-10)`. The ionisation constant of `NH_(4)^(+)` isA. `1.8xx 10^(9)`B. `5.55xx10^(-10)`C. `5.55xx10^(4)`D. `1.8xx10^(-5)` |
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Answer» Correct Answer - B `NH_(4)^(+)+H_(2)O hArr NH_(4)OH +H^(+)` `K_(h)=([NH_(4)OH][H^(+)])/([NH_(4)^(+)])` Since `[NH_(4)OH]=[H^(+)]` `:. K_(h)=([H^(+)]^(2))/ ([NH_(4)^(+)])` `NH_(4)^(+)` ionises as follows , `NH_(4)^(+) hArr NH_(3) +H^(+)` `K_(a)=([NH_(3)][H^(+)])/([NH_(4)^(+)])` Since `[NH_(3)]=[H^(+)]` `:. K_(a)=([H^(+)]^(2))/([NH_(4)^(+)])` `:. K_(a)=K_(h)=5.55 xx 10^(-10)` |
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