I:(1)/(1!)+(1+2)/(2!)+(1+2+2^(2))/(3!)+....=e^(2)-e II:(2)/(2!)+(2+4)/(3!)+(2+4+6)/(4!)+....=e

I:(1)/(1!)+(1+2)/(2!)+(1+2+2^(2))/(3!)+....=e^(2)-e II:(2)/(2!)+(2+4)

1.	I:(1)/(1!)+(1+2)/(2!)+(1+2+2^(2))/(3!)+....=e^(2)-e II:(2)/(2!)+(2+4)/(3!)+(2+4+6)/(4!)+....=e
Answer» only I is TRUE only II is true both I and II are true NEITHER I nor II true ANSWER :C

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I:(1)/(1!)+(1+2)/(2!)+(1+2+2^(2))/(3!)+....=e^(2)-e II:(2)/(2!)+(2+4)/(3!)+(2+4+6)/(4!)+....=e

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