(i)1/2N_(2(g))+ 3/2H_(2(g)) hArr NH_(3(g)), At 298 K is DeltaG^ө=-16.5 "kJ mol"^(-1), So find K_p. (ii)At 298 K is N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) , Calculate K_p and DeltaG^ө.

(i)1/2N_(2(g))+ 3/2H_(2(g)) hArr NH_(3(g)), At 298 K is DeltaG^ө=-16.

1.	(i)1/2N_(2(g))+ 3/2H_(2(g)) hArr NH_(3(g)), At 298 K is DeltaG^ө=-16.5 "kJ mol"^(-1), So find K_p. (ii)At 298 K is N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) , Calculate K_p and DeltaG^ө.
Answer» SOLUTION :(i)779.4 = `K_p` , (II)`K_p= 6.07xx10^5` and `DeltaG^ө=-33 "KJ MOL"^(-1)`