1.

I.12p^(2) - 7q =- 1 II.6q^(2) - 7q+2 =0

Answer»

<P>if` p lt q,`
if` p gt q,`
if`p le q,`
if` p ge q,`

Solution :(I) ` 12P^(2) - 7p =- 1 `
` rArr 12p^(2)-7p+1 = 0`
` rArr 12p^(2) -4p-3p+1 =0`
` rArr 4p(3p-1)-1(3p-1)=0`
` rArr (3p-1)(4p-1) = 0`
` rArr p = 1/4 or 1/3`
(II) ` 6q^(2) - 7q+2 = 0`
` rArr 6q^(2) -4q-3q+2 =0`
` rArr 2Q(3q-2)-1(3q-2) =0`
` rArr (3q-2)(2q-1) =0`
` rArrq = 2/3 or 1/2`
Obviously, ` p le q`


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