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I_(2) and Br_(2) are added to a solution containing Br^(-) and T^(-) ions what reaction will occur if I_(2)+2 e^(-)rarr2I^(-),E^(@)=+0.54 V and Br_(2)+2e^(-)rarrBr^(-),E^(2)=+1.09 V? |
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Answer» Solution :Since `E^(@)` of `Br_(2)` is higher than that of `I_(2)` THEREFORE `Br_(2)` has higher tendency to ACCEPT electrons that `I_(2)` converserly `I^(-)` IONS has a higher tendency to lose electrons than `Br^(-)` ion therefore the following reaction will occur `2I rarr_(2)^(@)+2e^(-)` `Br_(2)+2e^(-)rarr2Br^(-)` `2I^(-)+Br_(2)rarrI_(2)+2Br^(-)` In other words `I^(-)` ion will be oxidised to `I_(2)` while `Br_(2)` will be reduced to `Br^(-)` ions |
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