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I. ` 3x^(2) + 7x = 6 " "` II. ` 6(2y^(2)+1) = 17 y`A. if ` x lt y`B. if ` x gt y`C. if ` x = y`D. if ` x le y`

Answer» Correct Answer - D
I. ` 3x^(2) + 7x - 6 = 0`
or,` 3x^(2) + 9x - 2x - 6 = 0`
or,` (x+3)(3x-2) = 0`
or, ` x =- 3, 2//3`
II. ` 6(2y^(2)+1)= 17y`
or, ` 12y^(2) + 6 - 17y = 0`
or, ` 12y^(2)-9y-8y+6=0`
or, ` (4y-3)(3y-2) = 0`
or, ` y = 3//4, 2//3`
Hence, ` y ge x`


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