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(i) A powdered substance (A) on treatment with fusion mixture gives a green coloured compound (B). (ii) The solution of (B) in boiling water on acidification with dilute `H_(2)SO_(4)` gives a pink coloured compound `(C )`. `(iii)` The aqueous solution of (A) on treatment with NaOH and `Br_(2)-` water gives a compound (D). (iv) A solution of (D) in conc. `HNO_(3)` on treatment with lead peroxide at boiling temperature produced a compound (E) which was of the same coloure at that of (C). (v) A solution of (A) on treatment with a solution of barium chloride gave a white precipitate of compound (F) Which was insoluble in conc. `HNO_(3)` and conc. HCl. Which of the following is true for compound (C ).A. It oxidises ammonia to nitrogen dioxide in neutral mediumB. It is coloured and colour is due to d-d transitionC. It can be oxidised by ozoneD. It is obtained by alkaline fusion of pyrolusite in presence of air followed by electrolytic oxidation

Answer» Correct Answer - D
(A)`2MnO_4^(-)+2NH_3 to 2MnO_2+ N_2 + 2OH^(-)+2H_2O`
(B)`MnO_4^(-)` is pink coloured and colour is due to charge transfer.
(C )In `MnO_4^(-)` , central atom Mn is in highest oxidation state i.e. +VII and hence can not be oxidised.
(D)`MnO_2 + OH^(-)+O_2(air)overset("Fusion")toMnO_4^(2-)overset([e^-])toMnO_4^-`


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