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| 1. |
I am unable to find the time period of kinetic energy of SHM |
| Answer» You can refer SL Arora of class 11 physicsthe time period of the satellite is equals to circumference by velocity where c is equals to 2 by 4 bracket of Audi + 1 by root of GRE square by r d plus h and the final answer will be as 85 minutes | |