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I. `CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH` II. `CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3)` III. `CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3)` IV. `CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH` V. `CH_(3) - CH_(2) - O - CH_(2) - CH_(3)` VI. `CH_(3) - O - CH_(2) - CH_(2) - CH_(3)` VII. `CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3)` Identify the pairs of compounds that represents position isomerism. |
Answer» When two or more compounds differ in position of substituent atom or functional groups on the carbon skeleton, they are position isomers. In the given structure I and II, III and IV, and VI and VII are position isomers. I. `underset(1-"butanol")(CH_(3) - CH_(2) - CH_(2) - CH_(2) -OH)` II. `underset(2-"butanol")(CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3))` III. `underset(2-"methyl propanol"-2)(CH_(3) - underset(OH)underset(|)overset(CH_(3)) overset(|)(C) - CH_(3))` IV. `underset(2-"methyl propanol"-1)(CH_(3) - underset(CH_(3)) underset(|)(CH) - CH_(2) - OH)` VI. `underset("Methoxy propane")(CH_(3) - O - CH_(2) - CH_(2) - CH_(3))` and VII. `underset(underset("methoxy 1-methyl ethane")("Methoxy isopropane or"))(CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3))` |
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