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I. `CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH` II. `CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3)` III. `CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3)` IV. `CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH` V. `CH_(3) - CH_(2) - O - CH_(2) - CH_(3)` VI. `CH_(3) - O - CH_(2) - CH_(2) - CH_(3)` VII. `CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3)` Identify the pairs of compounds that represents position isomerism.

Answer» When two or more compounds differ in position of substituent atom or functional groups on the carbon skeleton, they are position isomers. In the given structure I and II, III and IV, and VI and VII are position isomers.
I. `underset(1-"butanol")(CH_(3) - CH_(2) - CH_(2) - CH_(2) -OH)` II. `underset(2-"butanol")(CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3))`
III. `underset(2-"methyl propanol"-2)(CH_(3) - underset(OH)underset(|)overset(CH_(3)) overset(|)(C) - CH_(3))` IV. `underset(2-"methyl propanol"-1)(CH_(3) - underset(CH_(3)) underset(|)(CH) - CH_(2) - OH)`
VI. `underset("Methoxy propane")(CH_(3) - O - CH_(2) - CH_(2) - CH_(3))` and VII. `underset(underset("methoxy 1-methyl ethane")("Methoxy isopropane or"))(CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3))`


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