1.

(I) CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(underset(OH)(|))(C H)-CH_(3) (III) CH_(3)- underset(underset(OH)(|))overset(overset(CH_(3))(|))(C )-CH_(3) (IV) CH_(3)- underset(underset(CH_(3))(|))(C H)-CH_(2)-OH (V ) CH_(3)-CH_(2)-O-CH_(2)-CH_(3) (VI) CH_(3)-O-CH_(2)-CH_(2)-CH_(3) (VII) CH_(3)-O- underset(underset(CH_(3))(|))(C H)-CH_(3) Which of the above compounds form pairs of metamers?

Answer»

Solution :`{:((V) UNDERSET("Ethoxy ethane")(CH_(3)-CH_(2)-O-CH_(2)-CH_(3))),((VI) underset("Methoxy propane")(CH_(3)-O-CH_(2)-CH_(2)-CH_(3))):}}` Metamers
`{:((VI) underset("Methoxy propane")(CH_(3)-O-CH_(2)-CH_(2)-CH_(3))),((VII) underset("Methoxy isopropane")(CH_(3)-O -underset(underset(CH_(3))(|))(CH)-CH_(3))):}}` Metamers
The position of `-O-` is changed in (V) ethoxy ETHENE and (VI) Methoxy propane, so they are metamers
In (VI) Methoxy propane and (VII) Methoxy isopropane the different in the no. of carbon on the either side of ether `-O-`


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