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(I) CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(underset(OH)(|))(C H)-CH_(3) (III) CH_(3)- underset(underset(OH)(|))overset(overset(CH_(3))(|))(C )-CH_(3) (IV) CH_(3)- underset(underset(CH_(3))(|))(C H)-CH_(2)-OH (V ) CH_(3)-CH_(2)-O-CH_(2)-CH_(3) (VI) CH_(3)-O-CH_(2)-CH_(2)-CH_(3) (VII) CH_(3)-O- underset(underset(CH_(3))(|))(C H)-CH_(3) Identify the pairs of compounds that represents position isomerism |
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Answer» SOLUTION :In these, there are functional group same but the position of functional group is different. (I) and (II) are position isomers. (I) `underset("Butan-1-ol")(CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH)` (II) `underset("Butan-2-ol")(CH_(3)-CH_(2)-underset(underset(OH)(|))(C H)-CH_(3))` In the following same function group present in both but the carbon CHAIN is different so, they are chain ISOMER (III) `underset("2-methyl prop-2-ol")(CH_(3)-underset(underset(OH)(|))overset(overset(CH_(3))(|))(C )-CH_(3))` (IV) `underset("2-methyl-propane-2-ol")(CH_(3)-underset(underset(CH_(3))(|))(CH)-CH_(2)-OH)` (VI) and (VII) both are ether but carbon chain is different so, (VI) and (VII) are chain isomers. (VI) `underset("Methoxy propane")(CH_(3)-O-CH_(2)-CH_(2)-CH_(3))` (VII) `underset("Methoxy isopropane")(CH_(3)-O-underset(underset(CH_(3))(|))(CH)-CH_(3))` |
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