(i) Derive ideal gas equation. (ii) CO_(2) gas cannot be liquified at room temperature. Give the reason.

(i) Derive ideal gas equation. (ii) CO_(2) gas cannot be liquified at

1.	(i) Derive ideal gas equation. (ii) CO_(2) gas cannot be liquified at room temperature. Give the reason.
Answer» Solution :(i) Ideal gas equation: The gaseous state is described completely using the following four variables T, P, V and n. Each gas law RELATES one variable of a gaseous sample to another while the other two variables are held constant. THEREFORE, combining all equations into a single equation will enable to account for the CHANGE in any or all of the variables. Boyle.s law: `Vprop(1)/(P)` Charles. law: `V prop T` Avogadro.s law: `Vpropn` We can combine these equations into the following general equation that describes the physical BEHAVIOUR of all gases. `Vprop(nT)/(P)` `V=(nRT)/(P)`,where R =Proportionately constant. The above equation can be rearranged to give PV = nRT - Ideal gas equation. Where, R is also known as Universal gas constant. (ii) Only below the critical temperature, by the application of pressure, a gas can be liquefied. `CO_(2)` has critical temperature as 303.98 K. Room temperature means (30 + 273 K) 303 K. At room temperature, (critical temperature) even by applying large amount of pressure `CO_(2)` cannot be liquefied. Only below the critical temperature, it can be liquefied. At room temperature, `CO_(2)` remains as gas.