(i) Find the adiabatic exponent gamma for mixture of mu_1 moles of monoatomic gas and mu_2 moles of a diatomic gas at normal temperature. (ii) An oxygen molecule is travelling in air at 300 K and 1 atm , and the diameter of oxygen molecule is 1.2xx10^(-10) m . Calculate the mean free path of oxygen molecule.

(i) Find the adiabatic exponent gamma for mixture of mu_1 moles of mon

1.	(i) Find the adiabatic exponent gamma for mixture of mu_1 moles of monoatomic gas and mu_2 moles of a diatomic gas at normal temperature. (ii) An oxygen molecule is travelling in air at 300 K and 1 atm , and the diameter of oxygen molecule is 1.2xx10^(-10) m . Calculate the mean free path of oxygen molecule.
Answer» Solution :`GAMMA=1/(sqrt2pind^(2))` We have to find the number density n by usin IDEAL GAS law `n=N/V=P/(kT)=(101.3xx10^(3))/(1.381xx10^(-23)xx300)=2.499xx10^(25)"molecules/m"^(3)` `gamma =1/(sqrt2xxpixx2.449xx10^(25)xx(1.2xx10^(-10))^(2))=1/(15.65xx10^(5))` `gamma=0.63xx10^(-6)m`