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(i)H_(2(g))+I_(2(g)) hArr 2HI_((g)) (ii)1/2H_(2(g)) + 1/2 I_(2(g)) hArr HI_((g)) (iii)nH_(2(g)) +nI_(2(g)) hArr 2HI_((g)) For these reactions the equilibrium constant is respectively K_c(1), K_c (2) and K_c (3) state their relation ? |
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Answer» Solution :(i)`K_c(1)=[HI]^2/([H_2][I_2])` (II)`K_c(2)=([HI])/([H_2]^(1/2)[I_2]^(1/2))=([HI]^2/([H_2][I_2]))^(1/2)=(K_c(1))^(1/2)` (III)`K_c(3)=[HI]^(2N)/([H_2]^n[I_2]^n)=([HI]^2/([H_2][I_2]))^n=(K_c(1))^n` Here , `K_c` (2) = `(K_c(1))^(1/2)` and `K_c(3)=(K_c(1))^n` |
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