1.

(I) How many unpaired electrons are present in the ground state of Fe3+ (z = 26), Mn2+ (z = 25) and argon (z = 18)? (II) Explain about the significance of de Broglie equation?

Answer»

(I) Fe → Fe3+ + 3e- 

Fe (Z = 26)

Fe3+ = number of electrons = 23

1s2 2s2 2p6 3s2 3p6 3d6 4s2 for Fe atom.

1s2 2s2 2p6 3s2 3p6 3d5 for Fe3+ ion.

So, it contain 5 unpaired electrons. 

Mn (Z = 25) Electronic configuration is

1s2 2s2 2p5 3s2 3p6 4s2 3d5

Mn → Mn2+ + 2e-

Number of unpaired electrons in Mn2+ = 5

Ar (Z = 18). Electronic configuration is

1s2 2s2 2p6 3s2 3p6

All orbitals are completely filled. So, no unpaired electrons in it.

(II) Significance of de Broglie equation:

1. λ = \(\frac{h}{mv}\) This equation implies that a moving particle can be considered as a wave and a wave can exhibit the properties of a particle. 

2. For a particle with high linear momentum (mv) the wavelength will be so small and cannot be observed.

3. For a microscopic particle such as an electron, the mass is of the order of 10-31 kg, hence the wavelength is much larger than the size of atom and it becomes significant. 

4. For the electron, the de Broglie wavelength is significant and measurable while for the iron ball it is too small to measure, hence it becomes insignificant.



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