1.

(i)In sulphur estimation , 0.157 g of organic compound gave 0.4813 g of BaSO_(4). What is the percentage of sulphur in organic compound ? (ii) 0.092 g of organic compound heating is carius tube and susequent ignition gave 0.111 g of Mg_(2)P_(2)O_(7) . calculate the percentage of phosphorus in organic compound.

Answer»

Solution :(i) Mass of `BaSO_(4) `=0.4813 g , mass of ORGANIC COMPOUND =0.157 g
% S `=(32xxW_(BaSO_(4))XX100)/(233xxW_("Substance"))=(32xx0.4813xx100)/(233xx0.157) =42.10`
(ii) Mass of organic compound =0.092 g , mass of `Mg_(2)P_(2)O_(7) `=0.111 g
% of P =`(62xxW_(Mg_(2)P_(2)O_(7))xx100)/(22xxW_("Substance"))=(62xx0.111xx100)/(222x0.092)=33.69`


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