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(i) \( \int_{0}^{1} \frac{d x}{3 x-4} \) |
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Answer» \(\int_0^1\frac{dx}{3x-4}\) = \([\frac{log|3x-4|}{3}]^1_0\) = \(\frac{1}{3}\)(log 1 - log 4) = \(\frac{-log\,4}{3}\)(∵ log 1 = 0) |
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