1.

I=Integral(sec(-4*x %2B 7)^2, x)

Answer»

I=⌡sec²(7-4x) dx

Let u=7-4x

dx = (-1/4)*(du)

I = (-1/4)*⌡sec²(u) du

Apply :⌡sec²(x) dx = tan(x)+C

Therefore :I = (-1/4)*(tan(u)) +C

I = (-1/4)*{tan(7-4x)} +C


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