`(i)intsec^(7) x. sin x dx" "(ii) int(1)/(sinx. cos^(2) x)dx`

1.	`(i)intsec^(7) x. sin x dx" "(ii) int(1)/(sinx. cos^(2) x)dx`
Answer» Correct Answer - `(i) (1)/(6) sec^(6) x+c " "(ii) sec x+ log \| " cosec " x- cot x \|+c`

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