1.

(i) K_(2)Cr_(2)O_(7)+KI+H_(2)SO_(4)to K_(2)SO_(4)+Cr_(2)(SO_4)_3+I_(2)+H_(2)O.

Answer»

Solution :
`K_(2)Cr_(2)O_7+6KI+H_(2)SO_4 to K_(2)SO_4+Cr_(2)(SO_4)_3+I_(2)+H_(2)O`
`K_(2)Cr_(2)O_7+6KI+H_2SO_4 to K_2SO_4+Cr_(2)(SO_4)_3+3I_2+H_2O`
`K_(2)Cr_(2)O_7+6KI+7H_(2)SO_4 to 4K_(2)SO_(4)+Cr_(2)(SO_4)_(3)+3I_(2)+7H_2O`.


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