(i)NH_4^(+)+H_2O hArr NH_3+H_3O^(+)equilibrium constant = K_1 (ii)NH_3 + H_2O hArr NH_4^(+) + OH^- equilibrium constant = K_2 Than write reaction and equilibrium constant obtain by addition of these two reaction.

(i)NH_4^(+)+H_2O hArr NH_3+H_3O^(+)equilibrium constant = K_1 (ii)NH_

1.	(i)NH_4^(+)+H_2O hArr NH_3+H_3O^(+)equilibrium constant = K_1 (ii)NH_3 + H_2O hArr NH_4^(+) + OH^- equilibrium constant = K_2 Than write reaction and equilibrium constant obtain by addition of these two reaction.
Answer» Solution :(i) + (ii) = `2H_2O hArr H_3O^(+) + OH^(-)` . The EQUILIBRIUM constant of this (i) and (ii)=K `THEREFORE K=(K_1xxK_2)=K_w=1.0xx10^(-14)`