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(i)`P+C("carbon")+Cl_(2)toQ+CO uarr` , (ii)`Q+H_(2)OtoR+HCl` (iii)`BN+H_(2)O to R+NH_(3)` , (iv)`Q+LiAIH_(4) to S+LiCl+ AlCl_(3)` (v)`S+H_(2)toR+H_(2) uarr` , (vi)`S+NaH to T` (`P,Q,R,S` and `T` do not represent their chemical symbols) Compound S is: (I) an odd compound (II) (III) an electron deficient compound (IV) a hybridized compound Choose the correct code:A. IIIB. I,IIIC. II,III,IVD. I,II,IV |
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Answer» Correct Answer - A (i)`B_(2)O_(3)(P)+3C+3Cl_(2) to 2BCl_(3) (Q) +3CO uarr` (ii)`BCl_(3)(Q)+3H_(2)O to H_(3)BO_(3)(R)+3HCl` (iii)`BN+3H_(2)O to H_(3)BO_(3)(R ) + NH_(3)` (iv)`4BCl_(3)(Q)+3LiAlH_(4) to 2B_(2)H_(6)(S)+3LiCl+3AlCl_(3)` (v)`B_(2)H_(6)+6H_(2)O to 2H_(3)BO_(3) (R)+6H_(2) uarr` (vi)`B_(2)H_(6)(S)+2NaH to 2NaBH_(4)(T)` |
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