(i) Pb(NO_(3))_(2) on strong heating loses 32.6% of its mass. Calculate the relative atomic mass of Pb. (ii) 1 volume of a gaseous compoundd comosed of C, H and N, on combustion in air produces 3 volumes CO_(2), 4.5 volumes water vapour and 0.5 volumes N_(2) gas. find the molecularr formula of the compound. [all volumes are measured under identiacl conditions of temperature and pressure].

(i) Pb(NO_(3))_(2) on strong heating loses 32.6% of its mass. Calculat

1.	(i) Pb(NO_(3))_(2) on strong heating loses 32.6% of its mass. Calculate the relative atomic mass of Pb. (ii) 1 volume of a gaseous compoundd comosed of C, H and N, on combustion in air produces 3 volumes CO_(2), 4.5 volumes water vapour and 0.5 volumes N_(2) gas. find the molecularr formula of the compound. [all volumes are measured under identiacl conditions of temperature and pressure].
Answer» Solution :(i) Let, relative ATOMIC mass of Pb=x. `underset(x+2(14+3xx16)g=(x+124)g)(Pb(NO_(3))_(2)) overset(DELTA)to underset((x+16)g)(PbO)+2NO_(2)+O_(2)` On DISSOCIATION of (x+124)g of `Pb(NO_(3))_(2)`, the weight decreases =`(x+124-x-16)g=108g` So, for 100g `Pb(NO_(3))_(2)`, the weight decreases `=((108xx100)/(x+124))g` As, `(100xx108)/(x+124)=32.6` or, x=207.3 (ii) N/A