1.

I s f ( x ) = 2 | x | + | x - 2 | \text { differentiable at } x = 1 ?

Answer»

at x=1, the value of f(x) = 2(x)+(2-x) = 2x+2-x = x+2

and f'(x) = 1

so, it is differentiable

can you plz note this answer on a paper and send it to me

by method

What is it , that is not understandable here ?

I am not understanding your answer can u plz answer this question briefly

at x = 1 , |x| = |1| so, it is +ve and mod will open like x , and |2-x| = |2-1| = |-1| , since it is -ve so, it will open with -ve sign as -(x-2) = 2-x

now add both 2x+2-x = x+2 and then differentiate it to see if you are getting any value or not.. here on differentiation it is coming 1.


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