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(i). State Kohlraush law of independent migration of ions (ii). Write Nernst’s equation for the following cell :Zn (s) I Zn2+ (aq) II Cu2+(aq) I Cu (s) (iii).Calculate ∆G0 for the following reaction:Mg (s) + Cu2+(aq) → Mg2+(aq) + Cu (s)[Given E0cell = +2.71 V, 1F = 96500 C/Mol] |
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Answer» (i) Kohlrausch's law of independent migration of ions states that the limiting molar conductivity of an electrolyte can be represented as the sum individual contributions of its cations & anions. (ii) Ecell = E0cell - \(\frac{0.0591}{2}log\frac{[zn^{2+}]}{[cu^{2+}]}\) (iii) ∆G = -nFE0 = - 2× 96500 × 2.71 = 523030 J |
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