1.

(i) What mass of hydrogen peroixde will be present in 2 L of a 5 molar solution ? (ii) Caluclate the mass of oygen which will be liberated by the decomposition of 200 mL of this solution.

Answer» `"Molarity of solution"=("Mass of" H_(2)O_(2)//"Molar mass")/("Volume of solution in litres")`
`(5 molL^(-1))=("Mass of" H_(2)O_(2)//(34g mol^(-1)))/(2L)`
`"Mass of "H_(2)O_(2)=(5 mol L^(-1))xx(2L)xx(34gmol^(-1))=340g`
Mass of oxygen `(O_(2))` liberated
`"Mass of "H_(2)O_(2)(l) "in 200mL of solution"=(340g)/(2L)xx(0.2L)=34g`
`underset(68g)2H_(2)O_(2)(l) to 2H_(2)O(l)+underset(32g)(O_(2)(g))`
`"Mass of" O_(2)(g) "liberated by 68g of" H_(2)O_(2)=32g`
`"Mass of" O_(2)(g) "liberated by 34g of" H_(2)O_(2)=16g`


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