(i) $ x^{2}-3 x-10=0 $(iii) $ \sqrt{2} x^{2}+7 x+5 \sqrt{2}=0 $(v)

1.	(i) $ x^{2}-3 x-10=0 $(iii) $ \sqrt{2} x^{2}+7 x+5 \sqrt{2}=0 $(v) $ 100 x^{2}-20 x+1=0 $
Answer» √2 x² +7x +5√2 = 0 ⇒√2 x² + 5x + 2x + 5√2 = 0 ⇒√2x² + 5x +√2√2x + 5√2=0 ⇒ x(√2x+5) +√2(√2x+ 5) =0 ⇒ (x+√2)(√2x+5)=0 That gives x=-√2 or x= -5/√2 Bro 2nd wala 100x2- 20x + 1 = 0 By splitting of middle terms method, 100x2 - 10x - 10x + 1 = 0 10x ( 10x - 1 ) - 1 ( 10x - 1 ) = 0 ( 10x - 1 ) ( 10x - 1 ) = 0 10x -1 = 0 ; 10x - 1 = 0 x = 1/10 ; x = 1/10 Therefore the roots are 1/10 and 1/10 Thnk bro

(i) $ x^{2}-3 x-10=0 $(iii) $ \sqrt{2} x^{2}+7 x+5 \sqrt{2}=0 $(v) $ 100 x^{2}-20 x+1=0 $

Answer»

√2 x² +7x +5√2 = 0

⇒√2 x² + 5x + 2x + 5√2 = 0

⇒√2x² + 5x +√2*√2*x + 5√2=0

⇒ x(√2x+5) +√2(√2x+ 5) =0

⇒ (x+√2)(√2x+5)=0

That gives x=-√2 or x= -5/√2

Bro 2nd wala

100x2- 20x + 1 = 0

By splitting of middle terms method,

100x2 - 10x - 10x + 1 = 0

10x ( 10x - 1 ) - 1 ( 10x - 1 ) = 0

( 10x - 1 ) ( 10x - 1 ) = 0

10x -1 = 0 ; 10x - 1 = 0

x = 1/10 ; x = 1/10

Therefore the roots are 1/10 and 1/10

Thnk bro