Ice crystallises in a hexagonal lattice having a volume of the unit cell as132 xx 10^(-24) cm^(3) . If density of ice at the given temperature is 0.92 g cm^(-3), the number ofH_(2)O molecules per unit cell is

Ice crystallises in a hexagonal lattice having a volume of the unit ce

1.	Ice crystallises in a hexagonal lattice having a volume of the unit cell as132 xx 10^(-24) cm^(3) . If density of ice at the given temperature is 0.92 g cm^(-3), the number ofH_(2)O molecules per unit cell is
Answer» <P>1 2 3 4 Solution :` p = ( Z XX M)/(a^(3) xxN_(0)) ` , the aim is to FIND Z. ` 0.92= ( Z xx 18)/((132 xx 10^(-24))( 6.02 xx 10^(23))) ` ` ( Z xx 18) /(132 xx 6.02 xx 10^(-1))` `or Z = ( 0.92 xx 132 xx 6.02 xx 10^(-1))/18= 4.06`