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Ice crystallises in a hexagonal lattice having a volume of the unit cell as 132xx10^(-24) cm^3. If density of ice at the given temperature is 0.92 g cm^(-3), then number of H_2O molecules per unit cell is

Answer»

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Solution :`rho=(ZxxM)/(a_3xxN_0)`. The AIM is to FIND Z.
`0.92xx(Zxx18)/((132xx10^(-24))(6.02xx10^23))`
`=(Zxx18)/(132xx6.02xx10^(-1))`
or `Z=(0.92xx132xx6.02xx10^(-1))/18=4.06`


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