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Ice melts at the rate of 5 kg per hour in a cold storage when the temperature outside is 300 K. Calculate the minimum power of the motor is to be used to drive a refrigerator to just prevent the melting of ice. Specific latent heat of usion of ice =3.3 xx 10 ^(5) J kg ^(-1) .[E.Q] |
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Answer» SOLUTION :`T_(1) = 300 , T_(2) = 273 K` Quantity of heat to be removed from the SINK `= Q _(2) = (ML)/(t)` `Q_(2) = (% xx 3>3 xx 10 ^(5))/(60 xx 60) = 458.33 J//S` |
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