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Iceberg floats in water with part of it submerged .What is the fraction of the volume of inceberg submerged if the density of ice is rho_(i)=0.917g//cm^(3). |
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Answer» Solution :Density of ice `rho_(ice)=0.17g//cm^(3)` Density of water `rho_(w)=1g//cm^(3)` Let volume of ICEBERG =V Let volume of water displaced by iceberg =.V. For body FLOATS on LIQUID, WEIGHT of iceberg = weight of water displaced by the submerged part by ice `thereforeVrho_(i)thetag=Vrho_(w)g` `therefore(V)/(V)=(rho_(ice))/(rho_(w))=(0.917)/(1)=0.917` |
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