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Identifity disporportionation reaction |
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Answer» Solution :Reaction in which the same substance is oixidised as well as reduced are CALLED DISPROPORTIONATION reaction writing the O.N of eachelement above its SYMBOLS in the following reaction we have (a) `C H_(4)+2O_(2)rarrCO_(2)+2H_(2)O (b) CH_(4)+4CI_(4)RARRC CI_(4) + 4HCI (c ) 2F_(2)+2OH^(-)rarr2F^(-)+OF_(2)+H_(2)O (d) 2 N O_(2)+2OH^(-)rarr NO_(2)^(-)+ANO_(3)^(-)+H_(2)O^(-2)` Thus in reaction (d) N is both oxidised as well as reduced since the O.N of N increases from +4 in `NO_(2)` to +5 in `NO_(3)^(-)` and decreases from+4 in `NO_(2)` to +3 in `NO_(2)^(-)` Thus option (d) is correct |
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