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Identify A to E and also explain the reaction involved. |
Answer» The substances from A to E are A = Cu, B = Cu`(NO_(3))_(2)`, C = `[Cu(NH_(3))_(4)]^(2+)`, D = `CO_(2)`, E = `CaCO_(3)` Reactions: (i) `CuCO_(3)overset(Delta)rarr CuO+CO_(2) xx2` (ii) `2CuO + CuS rarr underset([A])(3Cu) + SO_(2)` (iii) `underset ([A])(Cu) + 4HNO_(3) ("Conc.")rarr Cu underset([B])((NO_(3))_2)+2NO+2H_(2)O` (iv) `C underset([B])(u^(2+))+NH_(3) rarr undersetunderset(("Blue solution"))([C])([Cu(NH_(3))_(4)])` (v) `Ca(OH)_(2) + underset([D])(CO_(2)) rarr undersetunderset(("Milky"))([E]) (CaCO_(3)) + H_(2)O` (vi) `CaCO_(3) + H_(2)O + CO_(2) rarr Ca(HCO_(3))_(2)` |
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