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Identify correct pair from the following. (i) veca xx (vecb xx vecc)=(veca*vecb)vecc-(veca*vecc)vecb (ii) Projection of veca on vecb is (veca*vecb)/(|veca|) (iii) [hati +2hatj, hatj+2hatk, hatk +2hatj]=9 (iv) If vecr=veca+t vecb and vecr=vecc+s vecd are two skew lines then shortest distance between the lines is ([vecc-veca, vecb, vecd])/(|vecbxxvecd|) |
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Answer» (i) and (II) are CORRECT |
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