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Identify the correct statement (S) in relation to the following reaction : Zn+2HCIrarrZnCI_(2)+H_(2) |
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Answer» Solution :Writing the O.N of each element above its symbols we have `Zn+2HCIrarr Zn CI_(2)+H_(2)` (a) The O.N of Zn increases FORM 0 in Zn to +2 in`Zn CI_(2)` therefore Zn acts as a REDUCTANT thus option (c ) is not CORRECT (b) The O.N of CI does not change therfore it neither acts as a reductant nor an oxidant therefore option (b) is not correct (c ) The O.N of H decreae from +1 in `H^(+)` to 0 in `H_(2)` therefore `H^(+)` acts an oxidant thus option (c ) is correct (d) As explained in option (a) Zn acts as a reductant therefore it cannot act as an oxidant Thus option (c ) and (d) are correct |
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