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Identify the correct statemtn with referece to the given rection P_(4)+3OH^(-)+3H_(2)OrarrPH_(3)+3H_(2)PO_(2)^(-) |
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Answer» <P> Solution :Writing the O.N of each element above its symbbol we have`P_(4)^(0)+3OH^(-)+3H_(2)OrarrPH_(3)+3H_(2)PO_(2)^(-)` In this reaction O.N of P increses FORM 0 in `P_(4)` to +1 in `H_(2)PO_(2)^(-)`and decrease to -3in `PH_(3)` therefore P has undergone both oxidation as wellas reduction thus option (a) and (b) are wrong and option (c ) is correct further O.N (d) id correct in other WORDS option (c ) and (d) are correct reduction thusoption (d) is correct in other words option(c ) and (d) are correct |
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